Simple Aptitude Question ( which i cannot solve)
Simple Aptitude Question ( which i cannot solve)
Can someone please suggest a solution format for this question
A pet store has
24 puppies
6 are small
12 are brown
15 have long hair
there is one small brown puppy with long hair
there are two small brown puppies NOT with long hair
there are two small puppies with long hair but are not brown
how many puppies are brown, have long hair but are not small
ANS 3.
A pet store has
24 puppies
6 are small
12 are brown
15 have long hair
there is one small brown puppy with long hair
there are two small brown puppies NOT with long hair
there are two small puppies with long hair but are not brown
how many puppies are brown, have long hair but are not small
ANS 3.
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Re: Simple Aptitude Question ( which i cannot solve)
Draw a Venn diagram and you will see that the solution is not unique.
Re: Simple Aptitude Question ( which i cannot solve)
thanks for the reply David. I have tried a Venn Diagram (obviously) without success; hence ths post. It's been a while since I've worked such magic but given the lead i'll give it another shot.
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Re: Simple Aptitude Question ( which i cannot solve)
Apologies. I re-read the question and the solution is unique. A Venn diagram will help a lot. You can use a little bit of algebra to get you over the line.
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Re: Simple Aptitude Question ( which i cannot solve)
Solution:
Hope that helps.
PRIME_BBCODE_SPOILER_SHOW PRIME_BBCODE_SPOILER:
Draw simple 3 circle venn diagram, labelled Sm/Br/Lo.
This has 7 areas:
A = Sm
B = Sm & Br
C = Br
D = Sm & Lo
E = Sm & Br & Lo
F = Br & Lo
G = Lo
Translating the rules, in the order given
a) A+B+C+D+E+F+G = 24
b) A+B+D+E = 6
c) B+C+E+F = 12
d) D+E+F+G = 15
e) E = 1
f) B = 2
g) D = 2
From (b), we can see A=1.
From (c), we have C+F = 9
From (d), we have F+G = 12
From (a), we now have C+F+G = 18
(C+F)+(F+G) = 21, therefore, F=3.
From (c), C=6 and from (d) G=9.
"how many puppies are brown, have long hair but are not small?". That's F in our workings, which is 3.
This has 7 areas:
A = Sm
B = Sm & Br
C = Br
D = Sm & Lo
E = Sm & Br & Lo
F = Br & Lo
G = Lo
Translating the rules, in the order given
a) A+B+C+D+E+F+G = 24
b) A+B+D+E = 6
c) B+C+E+F = 12
d) D+E+F+G = 15
e) E = 1
f) B = 2
g) D = 2
From (b), we can see A=1.
From (c), we have C+F = 9
From (d), we have F+G = 12
From (a), we now have C+F+G = 18
(C+F)+(F+G) = 21, therefore, F=3.
From (c), C=6 and from (d) G=9.
"how many puppies are brown, have long hair but are not small?". That's F in our workings, which is 3.
Re: Simple Aptitude Question ( which i cannot solve)
The solution is only unique if you assume that there are no puppies which are not small, are not brown and do not have long hair.
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Re: Simple Aptitude Question ( which i cannot solve)
Well done Eva - Very true!
Re: Simple Aptitude Question ( which i cannot solve)
Well done ,,,,
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Re: Simple Aptitude Question ( which i cannot solve)
There is a point of aberration in this logo-gram!
Because meaning puppy is the small dog.
Result : All of puppies are small.
Avina
Because meaning puppy is the small dog.
Result : All of puppies are small.
Avina
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Re: Simple Aptitude Question ( which i cannot solve)
All mice a are small, but there are big mice and small mice. The same goes for puppies.Avina wrote: Because meaning puppy is the small dog.
Result : All of puppies are small.
Re: Simple Aptitude Question ( which i cannot solve)
I quickly looked. I have seen like this ago, but there were the points of diversion.
I solved and it's answer "3" , and so I think it's answer must be check by the law of probability.
Avina
I solved and it's answer "3" , and so I think it's answer must be check by the law of probability.
Avina
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Re: Simple Aptitude Question ( which i cannot solve)
No. Check the spoilered text in the 5th post. There is no "probability"!Avina wrote:I think it's answer must be check by the law of probability.
The only caveat is Ekaterin's comment:
"The solution is only unique if you assume that there are no puppies which are not small, are not brown and do not have long hair."
This problem is solved, and closed.